Formulae for Hyperdrive, Transwarp and Slipstream

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Enola Straight
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Formulae for Hyperdrive, Transwarp and Slipstream

Post by Enola Straight »

According to Graham Kennedy's site :roll: the formula for calculating a transwarp factor is basically Tw F (x)=x^4*x^1/3.

What are the formula for Hyperdrive and Quantum Slipstream Drive?
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Post by Robert Walper »

I haven't the faintest clue.

However, I thought I should mention that while playing with a calculator, I realized that if one applies a exponent of 4 to any warp factor(ie: 1, 9.9, etc), you get a factor of C which seems similar to some factors others have suggest for warp.
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Post by Master of Ossus »

It is unclear. The linear scale for hyperdrives, as demonstrated in the RPG, is obviously not accurate. From EU sources, it appears to be some sort of a logarithmic scale, or something even stranger.
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Post by Typhonis 1 »

umm wasnt Warp factor once the Warp speed cubed IE warp 2 was 8c
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Re: Formulae for Hyperdrive, Transwarp and Slipstream

Post by Durandal »

Enola Straight wrote:According to Graham Kennedy's site :roll: the formula for calculating a transwarp factor is basically Tw F (x)=x^4*x^1/3.

What are the formula for Hyperdrive and Quantum Slipstream Drive?
Therefore Warp 10 is a finite number. Kennedy's formula fails.
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Post by Durandal »

Addendum: The proper formula would be an asymptotal one, where as x gets closer and closer to 10, y grows infinitely larger. Also, depending on the relationship between warp and transwarp, you could have a warp function on one side of the asymptote, and a transwarp function on the other side, so long as each function is undefined at x = 10. Kennedy's formula does not satisfy this requirement, therefore it is wrong.
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Post by Darth Servo »

Hyperdrive: unknown, not enough data to generate an actual formula.

Transwarp, regular warp, slipstream, etc: whatever the writers want it to be for this week's episode. :P
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Post by The Nomad »

Durandal wrote:Addendum: The proper formula would be an asymptotal one, where as x gets closer and closer to 10, y grows infinitely larger. Also, depending on the relationship between warp and transwarp, you could have a warp function on one side of the asymptote, and a transwarp function on the other side, so long as each function is undefined at x = 10. Kennedy's formula does not satisfy this requirement, therefore it is wrong.
What about an analogy with relativistic/newtonian mechanics ? The formula is accurate for low warp speeds, but as warp gets higher than, say, factor 8, the formula changes and y tend to infinite as x gets close to 10 ?
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Post by SWPIGWANG »

hyperdrive = max speed 1.5c DONE :P
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Post by Darth Wong »

We've just learned that GK cannot perform a simple curve-fit. And this guy teaches science?
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Post by Patrick Degan »

I sort of liked Darth Wong's suggestion for the Voyager FTL formula: sacrificing live chickens to the Warp Gods while speaking incantations in the tongue of the Old Ones. 8)
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Post by Enola Straight »

TOS warp formula: Wf (x)=(x^3)*c

TNG/DS9/VOY warp formula: Wf (x)=((x^3)*(x^1/3))*c from warp factors 1 to 9, inclusive.

Between 9 and 10 the formula is WAY to complicated...rising asymptotically to infinity.
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Post by Durandal »

The Nomad wrote:
Durandal wrote:Addendum: The proper formula would be an asymptotal one, where as x gets closer and closer to 10, y grows infinitely larger. Also, depending on the relationship between warp and transwarp, you could have a warp function on one side of the asymptote, and a transwarp function on the other side, so long as each function is undefined at x = 10. Kennedy's formula does not satisfy this requirement, therefore it is wrong.
What about an analogy with relativistic/newtonian mechanics ? The formula is accurate for low warp speeds, but as warp gets higher than, say, factor 8, the formula changes and y tend to infinite as x gets close to 10 ?
I dunno, maybe. I guess. How hard is it to create a formula with a denominator of x-10, though?
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Post by Specialist »

Here is the real formula that I got from here.

W = (SQRT(10)/SQRT(10-ABS(B5))-1)*[Maximum velocity possible using warp]

Code: Select all

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Post by HemlockGrey »

I believe that gutteral shriek was the sound of this entire topic screeching over my head.
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Post by Specialist »

Grr :x

Replace b5 with number greater than equal 0 and less than 10

W = (SQRT(10)/SQRT(10-ABS(V))-1)*[Maximum velocity possible using warp]

Code: Select all

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Post by Durandal »

The Specialist wrote:W = (SQRT(10)/SQRT(10-ABS(V))-1)*[Maximum velocity possible using warp]
This doesn't work, as the denominator at x = 10 is negative. Unless you meant this:

v(x) = [C/(sqrt(10 - x))] - 1
where
C = (sqrt(10))(V_max)
on the domain
D: {x| 0 < x < 10}

That function would approach infinity rather quickly because of the square root on the bottom, though. Perhaps too rapidly, but it's still better than Kennedy's.
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Post by Vertigo1 »

IIRC, there is a fixed number stated for Transwarp. In one episode of Voyager, the Delta Flyer was clocked at 400LY/sec as stated by Lameway. It was in part 2 of the episode where a borg queen wanted seven to rejoin the collective.
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Post by Durandal »

Just remembered, that formula doesn't work because it includes the term for maximum achievable speed using warp. That term would be the local maximum of the function. The local max is a point where the derivative is zero. In the case of a function describing warp factors, the function must keep increasing exponentially as it goes to x = 10. The slope of the tangent line, therefore, would get closer and closer to infinity, which is why a local max can never exist at an asymptote.
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