Formulae for Hyperdrive, Transwarp and Slipstream
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Formulae for Hyperdrive, Transwarp and Slipstream
According to Graham Kennedy's site the formula for calculating a transwarp factor is basically Tw F (x)=x^4*x^1/3.
What are the formula for Hyperdrive and Quantum Slipstream Drive?
What are the formula for Hyperdrive and Quantum Slipstream Drive?
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It is unclear. The linear scale for hyperdrives, as demonstrated in the RPG, is obviously not accurate. From EU sources, it appears to be some sort of a logarithmic scale, or something even stranger.
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Re: Formulae for Hyperdrive, Transwarp and Slipstream
Therefore Warp 10 is a finite number. Kennedy's formula fails.Enola Straight wrote:According to Graham Kennedy's site the formula for calculating a transwarp factor is basically Tw F (x)=x^4*x^1/3.
What are the formula for Hyperdrive and Quantum Slipstream Drive?
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Addendum: The proper formula would be an asymptotal one, where as x gets closer and closer to 10, y grows infinitely larger. Also, depending on the relationship between warp and transwarp, you could have a warp function on one side of the asymptote, and a transwarp function on the other side, so long as each function is undefined at x = 10. Kennedy's formula does not satisfy this requirement, therefore it is wrong.
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Hyperdrive: unknown, not enough data to generate an actual formula.
Transwarp, regular warp, slipstream, etc: whatever the writers want it to be for this week's episode.
Transwarp, regular warp, slipstream, etc: whatever the writers want it to be for this week's episode.
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What about an analogy with relativistic/newtonian mechanics ? The formula is accurate for low warp speeds, but as warp gets higher than, say, factor 8, the formula changes and y tend to infinite as x gets close to 10 ?Durandal wrote:Addendum: The proper formula would be an asymptotal one, where as x gets closer and closer to 10, y grows infinitely larger. Also, depending on the relationship between warp and transwarp, you could have a warp function on one side of the asymptote, and a transwarp function on the other side, so long as each function is undefined at x = 10. Kennedy's formula does not satisfy this requirement, therefore it is wrong.
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We've just learned that GK cannot perform a simple curve-fit. And this guy teaches science?
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I dunno, maybe. I guess. How hard is it to create a formula with a denominator of x-10, though?The Nomad wrote:What about an analogy with relativistic/newtonian mechanics ? The formula is accurate for low warp speeds, but as warp gets higher than, say, factor 8, the formula changes and y tend to infinite as x gets close to 10 ?Durandal wrote:Addendum: The proper formula would be an asymptotal one, where as x gets closer and closer to 10, y grows infinitely larger. Also, depending on the relationship between warp and transwarp, you could have a warp function on one side of the asymptote, and a transwarp function on the other side, so long as each function is undefined at x = 10. Kennedy's formula does not satisfy this requirement, therefore it is wrong.
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Here is the real formula that I got from here.
W = (SQRT(10)/SQRT(10-ABS(B5))-1)*[Maximum velocity possible using warp]
W = (SQRT(10)/SQRT(10-ABS(B5))-1)*[Maximum velocity possible using warp]
Code: Select all
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Grr
Replace b5 with number greater than equal 0 and less than 10
W = (SQRT(10)/SQRT(10-ABS(V))-1)*[Maximum velocity possible using warp]
Replace b5 with number greater than equal 0 and less than 10
W = (SQRT(10)/SQRT(10-ABS(V))-1)*[Maximum velocity possible using warp]
Code: Select all
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This doesn't work, as the denominator at x = 10 is negative. Unless you meant this:The Specialist wrote:W = (SQRT(10)/SQRT(10-ABS(V))-1)*[Maximum velocity possible using warp]
v(x) = [C/(sqrt(10 - x))] - 1
where
C = (sqrt(10))(V_max)
on the domain
D: {x| 0 < x < 10}
That function would approach infinity rather quickly because of the square root on the bottom, though. Perhaps too rapidly, but it's still better than Kennedy's.
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IIRC, there is a fixed number stated for Transwarp. In one episode of Voyager, the Delta Flyer was clocked at 400LY/sec as stated by Lameway. It was in part 2 of the episode where a borg queen wanted seven to rejoin the collective.
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Just remembered, that formula doesn't work because it includes the term for maximum achievable speed using warp. That term would be the local maximum of the function. The local max is a point where the derivative is zero. In the case of a function describing warp factors, the function must keep increasing exponentially as it goes to x = 10. The slope of the tangent line, therefore, would get closer and closer to infinity, which is why a local max can never exist at an asymptote.
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