And what did the do to the coconut?kheegan wrote:Matt Huang wrote:relative to an unladen swallow going at terminal velocity.Shinova wrote:
Relative to whom
European or African swallow?
-Gunhead
Moderator: Alyrium Denryle
And what did the do to the coconut?kheegan wrote:Matt Huang wrote:relative to an unladen swallow going at terminal velocity.Shinova wrote:
Relative to whom
European or African swallow?
Where does it go when you keep the electicity on?Darth Servo wrote:Where does the "light go" when you turn off your electricity?
-------Crap I Drew on my Lunch BreakJin Wicked wrote:Was bloody Scrooge McDuck a goth, too? Did he ever write bad poetry in his basement with the Monopoly Guy?
"Go directly to jail. Do not pass 'Go'. Do not collect two hundred dollars."
"Life is pain."
Sort of. The Schwarzschild solution is the classic simple black hole, and it does have a brief wormhole in its maximal analytic extension. What this means, roughly, is that the Schwarzschild solution is taken literally and extended it into the infinite past and future, then it looks like two asymptotically flat regions of spacetime briefly connected by a 'bridge'--a wormhole. The problem is that interpreting this as anything more than a mathematical curiosity is unjustified, since real black holes are formed by gravitational collapse of matter, and therefore simply do not exist in the infinite past (or, for that matter, infinite future either, as predicted by Hawking radiation).Junghalli wrote:Uh, OK, so the wormhole inside a black hole is a myth?
That depends. Relative to an external observer, the light ray never reaches the horizon in the first place, so in a sense it doesn't go anywhere. If we look at it from the light ray's viewpoint, the only reasonable answer seems to be that it is converted directly into spacetime curvature. Spacetime curvature is described by the four-dimensional rank-4 Riemann tensor. You can think of this beast as a kind of "4x4x4x4 matrix" instead of standard two-dimensional nxm matrices, although there are fundamental differences in how tensors behave (but they aren't important right now). Despite having 4^4 = 256 components, only twenty of them are actually independent. What the Einstein field equation says is that there is a relationship between the mass/energy contained in space (the stress-energy-momentum tensor) and the trace of the Riemann tensor, in the analogous manner that the trace operation is defined on matrices, except in this case it produces a rank-2 tensor called the Ricci curvature tensor. The Ricci tensor only determines ten of those twenty independent components--in other words, the Einstein field equation is actually ten equations in twenty unknowns. This obviously leads to an underdetermined solution, which is where black holes come in. Isolated black holes are actually all vacuum solutions--they have no matter content anywhere (stress-energy tensor vanishes), and have no Ricci curvature either (as they must by the Einstein field equation), but they do have nonzero Weyl curvature--roughly, those ten other components of the Riemann curvature. (This grossly oversimplifies matters, but it should be sufficient.)tumbletom wrote:This may sound like a stupid question, but since black holes can suck in light, where does that light go?
True, light lenses around a black hole, so much that what one would see is a distorted view of the stars on the other side of the black hole, but that does not not mean that light gets "stuck" around the block hole. The only place for light to get "stuck" would be at exactly three-halves of the black hole's Schwarzschild radius, but this condition is so unstable that any pertubation would destroy it. Not only are conditions never so perfect, but light itself has has physical size (the wavelength). This question has actually come up fairly recently here. Still, even if light gettings "stuck" is unrealistic, it may be interesting to see how many orbital revolutions are possible if pertubations are kept within a certain range.InnocentBystander wrote:Acutally... I think the light gets "stuck in orbit" so to speak. There is a picture in my old physics books, mabye I'llscan it tonight, doubtful. We are pretty sure that gravity bends light. In the case of a black hole the light gets bent very far... so far in fact that it would appear to be going in orbit around it.
That would be putting it mildly. The thing inside a black hole is a singularity. You get close a black hole, you'll be ripped to shreds by tidal forces, then your shreds will be ripped to shreds, producing x-rays in the process, then you'll go into the black hole and fall onto the singularity, forever(*) disappearing from the universe.Junghalli wrote:Uh, OK, so the wormhole inside a black hole is a myth?Darth Wong wrote:You've been watching too much sci-fi.
So a question from a non-science type guy: The Romulans are depicted in ST as using a quantum singularity as a power source. With enough shielding is this even possible? Or more technobabble?GrandMasterTerwynn wrote:That would be putting it mildly. The thing inside a black hole is a singularity. You get close a black hole, you'll be ripped to shreds by tidal forces, then your shreds will be ripped to shreds, producing x-rays in the process, then you'll go into the black hole and fall onto the singularity, forever(*) disappearing from the universe.Junghalli wrote:Uh, OK, so the wormhole inside a black hole is a myth?Darth Wong wrote:You've been watching too much sci-fi.
* - Well, this is a lie. You'll eventually make it out again . . . just one or two particles at a time, due to Hawking radiation.
Hawking radiation, as he mentioned, means, a black hole will emit energy.Tommy J wrote:So a question from a non-science type guy: The Romulans are depicted in ST as using a quantum singularity as a power source. With enough shielding is this even possible? Or more technobabble?
For an order of magnitude guestimate, you can use the equation t=(m^3)/(1000) where t is how long it will take the black hole to evaporate in seconds and m is the black hole's mass in megagrams (1000 kilograms, about a ton.). This assums it doesn't get any more matter added in.Mayabird wrote:... (there's an equation somewhere to estimate how long into the future, but it's a ridiculously large amount of time) ...
...what the OoM equation tells us is that the smaller a black hole is, the faster it sheds energy, to the point where a million kilo black hole will turn into very hard radiation in about one second. When a black hole gets quite small it's gravity is fairly trivial (stand next to a mountain. Did you fall over? Right.) except when you get close, where it goes from noticable to insane quickly, and will have very rediculous tidal forces.SirNitram wrote:Hawking radiation, as he mentioned, means, a black hole will emit energy.Tommy J wrote:So a question from a non-science type guy: The Romulans are depicted in ST as using a quantum singularity as a power source. With enough shielding is this even possible? Or more technobabble?
Of course, this requires a means to shield against the shape of spacetime, which is fucking absurd. Not to mention the weight issues.
True, but a black hole where you wouldn't notice the tidal forces even as you passed through the event horizon would need to be thousands of times more massive than What'sitsname, the Milky Way core black hole.SPOOFE wrote:I've read some theories that postulated that in the case of a sufficiently large black hole - such as the one at the center of the galaxy - you could pass through the event horizon and not even notice.Of course the intense gravity would kill you long before time dilation kicks in but why be picky.
Before anyone points it out, yes you need EM shielding on antimatter type fuel, but with a black hole you're storing a looooot more mass. Also the energy collection has to happen withing the EM container, or both be the same device. Also you can never turn it off; with anti-matter if you don't have fuel in the container it doesn't need to be on, so if there's a problem you can repair it when there's nothing inside.Sriad wrote:As for carrying the thing, you need to give it an EM charge (easy enough) and then suspend it using an opposite charge; this would cause problems with other electrical equipment and computer systems on the ship. (<-understatement)
What are those pics from?Galvatron wrote:Don't listen to these guys! It's quite clear that a black hole is a portal to either Heaven or Hell and I have pics to prove it...
This is a black hole. Note the spaceship being sucked into it...
This and this are where you'll end up if you're a prick and get sucked in. Hell looks like a depressing place...
This is the hallway of glass you'll enter on your way to Heaven. If you're lucky, you might even see this angelic apparition leading the way. Finally, if it's not your time to die, the hallway will lead to the other end of the black hole (a white hole)...
And this is what the while hole looks like from the outside...
I hope I've helped.
A) Yes, it is possible. Though it's less of a power source than an incredibly inefficient battery. (To use a black hole for a power source requires that you first be able to create them in the first place, and that takes a phenomenal amount of energy. Though you could "recharge" the battery, at least . . . and it's not very particular about what you're shoveling into it. Sortof like Mr. Fusion from Back to the Future.)Tommy J wrote:So a question from a non-science type guy: The Romulans are depicted in ST as using a quantum singularity as a power source. With enough shielding is this even possible? Or more technobabble?GrandMasterTerwynn wrote:That would be putting it mildly. The thing inside a black hole is a singularity. You get close a black hole, you'll be ripped to shreds by tidal forces, then your shreds will be ripped to shreds, producing x-rays in the process, then you'll go into the black hole and fall onto the singularity, forever(*) disappearing from the universe.Junghalli wrote: Uh, OK, so the wormhole inside a black hole is a myth?
* - Well, this is a lie. You'll eventually make it out again . . . just one or two particles at a time, due to Hawking radiation.
Mount the black hole in the front of the ship and you could actually use it as your drive. Just let the ship fall toward the black hole while pushing the black hole in front of it as it moves, and use manuevering thrusters when you want to change direction.GrandMasterTerwynn wrote: And worse, how you accelerate the black hole at the exact same rate that you accelerate the starship (lest the black hole wander into the walls of its containment chamber due to it's incredible inertia . . . which would probably solve your maneuvering problems really quickly, while introducing a whole host of new ones (namely a hole in the side of your ship, and the fact that you are now out of power.)
That's a violation of Conservation of Momentum. The force required to keep the black hole ahead of the ship would be equal to the force that the black hole is exerting on the ship, thus producing no net motion.Junghalli wrote: Mount the black hole in the front of the ship and you could actually use it as your drive. Just let the ship fall toward the black hole while pushing the black hole in front of it as it moves, and use manuevering thrusters when you want to change direction.
Wrong, wrong, wrong. Two big problems:Junghalli wrote:Mount the black hole in the front of the ship and you could actually use it as your drive. Just let the ship fall toward the black hole while pushing the black hole in front of it as it moves, and use manuevering thrusters when you want to change direction.GrandMasterTerwynn wrote: And worse, how you accelerate the black hole at the exact same rate that you accelerate the starship (lest the black hole wander into the walls of its containment chamber due to it's incredible inertia . . . which would probably solve your maneuvering problems really quickly, while introducing a whole host of new ones (namely a hole in the side of your ship, and the fact that you are now out of power.)
Didn't somebody once speculate that the Death Star was powered by a black hole power plant?