Hawking radiation

The Nomad · Post by **The Nomad** » 2003-07-13 04:37am

Isn't there an easy formula to calculate the amount of radiation produced by a black hole of given mass/radius ( I already have the formula for the Shwartzwild radius ) ?

The Nomad · Post by **The Nomad** » 2003-07-14 04:02am

How. I am amazed at the insane success of my question.

The Nomad · Post by **The Nomad** » 2003-07-14 04:30am

Could I use the luminosity of the black hole ?

The formula is L~= ( 3.568e32 )/M² W...

Oddly enough, that would mean that the lighter the black hole, the higher the amount of Hawking radiation it radiates... I knew that individual photons of Hawking rad were more energetic as mass decreased, but I'd have thought that the higher surface would mean more quanta emission... well, I stand corrected, and I apparently have enough formulas to get a loooot of fun trying to calculate all the stuff from my scifi

...

Lord Edam · Post by **Lord Edam** » 2003-07-14 08:32am

The Nomad wrote:Could I use the luminosity of the black hole ?

yes, you could. The hawking radiation a black hole puts out is the same as the black body radiation, which after a bit of playing with masses comes out to the luminosity.

Oddly enough, that would mean that the lighter the black hole, the higher the amount of Hawking radiation it radiates...

aka "the runaway effect". A lot of people don't believe you when you say black holes get hotter as they lose energy, but they do.

edit: and I forgot the whole point of this...the link explaining it.thinkquest