Anyone wanna give their oppinion of this?

[Rightous Fist Of Heaven]

By Virus-X

I didn't ask you, and you didn't provide calculations to back it. There is no way you can accurately get an answer for lesser gunnery by "...scaling..." it to larger gunnery, and vice-versa. Making an assumption like that is stupid, considering, usually, they turn out to be incorrect. First of all, there is no indication or proof that the turbolasers mounted on the Imperial/Victory-classes of star destroyer are any more powerful than those mounted on any other ship. If you can prove it, show it, don't just make unfounded claims, or else I have no reason to believe you, and neither does anyone else. Second of all, at best, a heavy turbolaser (spell it out for people that don't know what you're talking about, unless you're tryin to hide something; not everybody [including me] has been listening from the beginning) is, at best, 200 gigatons of TNT equivalent. Remember, a double turbolaser fires with both barrels, while a quad turbolaser fires with 2 barrels alternating in pairs. The quad turbolaser is 200 gigatons of TNT. A double turbolaser only has 2 barrels, and there is no write-up saying they're more powerful than the used pair from the quad turbolaser. A single-barrel turbolaser would have only 100 gigatons of TNT equivalent behind each blast. A double heavy turbolaser would be about 400 gigatons, but I've never heard such a weapon existing; probably because they don't have the facilities to power it. If you read the Essential Guide to Weapons and Technology, it's a hardship and a hazard powering regular turbolasers. Your "...Teratonns..." estimate is total nonsense, especially when you show no credible (or even incredible) calculations to back them.
Virus-X

Oh, really? I'd like to see that calculation. Especially how you calculated such things as the yield of Borg torpedoes, in light of the fact that I don't recall seeing any episode of Star Trek, yet, where they were used. I remember seeing beams and pulses of energy, but never seen torpedoes used, not even against Species 8472. So, how you got the mathematical calcualtions for those, I'd love to see, including the formula. Then, I'd like to see how you got the calculations for the shield power of the Imperial-class star destroyer, and the hows/whys of why you think it would take a Borg cube any significant amount of time to defeat and assmilate them. Finally, I'd like to see where you get your estimation of Borg shield power, and why you for some unknown reason believe it would take "...9 waves of 1000 Borg cubes..." of anything Borg to defeat an Imperial or Imperial II-class star destroyer? Your calculations don't have to be "...perfect...", just accurate and credible.


One of the funniest things he does is that the uses TDiC but claims that there are fireballs the size of 25% of the planets surface around there somewhere.

[meNNis]

ehh... i would gladly give my opinion... but im too damn lazy to read it all this early in the morning sorry

[Ender]

By Virus-X

I didn't ask you, and you didn't provide calculations to back it. There is no way you can accurately get an answer for lesser gunnery by "...scaling..." it to larger gunnery, and vice-versa. Making an assumption like that is stupid, considering, usually, they turn out to be incorrect.

Prove it wrong, then we'll talk

First of all, there is no indication or proof that the turbolasers mounted on the Imperial/Victory-classes of star destroyer are any more powerful than those mounted on any other ship. If you can prove it, show it, don't just make unfounded claims, or else I have no reason to believe you, and neither does anyone else.

Look at the size of the guns on the Acclamator, they are the same size as the MTLs on an ISD.

Second of all, at best, a heavy turbolaser (spell it out for people that don't know what you're talking about, unless you're tryin to hide something; not everybody [including me] has been listening from the beginning) is, at best, 200 gigatons of TNT equivalent.

No, that was a MTL

Remember, a double turbolaser fires with both barrels, while a quad turbolaser fires with 2 barrels alternating in pairs.

Funny, I only saw one beam shoot out of the trench quad when they were shooting at asteroids in ESB. I love how you say scaling is wrong, then try to scale up fire rates from an X-wing.

The quad turbolaser is 200 gigatons of TNT. A double turbolaser only has 2 barrels, and there is no write-up saying they're more powerful than the used pair from the quad turbolaser. A single-barrel turbolaser would have only 100 gigatons of TNT equivalent behind each blast. A double heavy turbolaser would be about 400 gigatons, but I've never heard such a weapon existing; probably because they don't have the facilities to power it. If you read the Essential Guide to Weapons and Technology, it's a hardship and a hazard powering regular turbolasers.

Erroneous conclusions built from errors

Your "...Teratonns..." estimate is total nonsense, especially when you show no credible (or even incredible) calculations to back them.
Virus-X

Oh, really? I'd like to see that calculation. Especially how you calculated such things as the yield of Borg torpedoes, in light of the fact that I don't recall seeing any episode of Star Trek, yet, where they were used. I remember seeing beams and pulses of energy,

Those pulses are Borg Force Plasma, aka Borg plasma torpedoes, aka Borg torps

but never seen torpedoes used, not even against Species 8472. So, how you got the mathematical calcualtions for those, I'd love to see, including the formula.

OOC: I've been using numbers I see here, and I have asked for what people think and why, but the thread was largely ignored

Then, I'd like to see how you got the calculations for the shield power of the Imperial-class star destroyer,

Bean's work based on the Moonshadow in Isard's revenge

and the hows/whys of why you think it would take a Borg cube any significant amount of time to defeat and assmilate them.

Because all borg weapons rate below the threshold, meaning that a single cube could never punch through

Finally, I'd like to see where you get your estimation of Borg shield power,

Numer of torps it takes to get through their shields and the yield of those torp. It is simple math.

and why you for some unknown reason believe it would take "...9 waves of 1000 Borg cubes..." of anything Borg to defeat an Imperial or Imperial II-class star destroyer? Your calculations don't have to be "...perfect...", just accurate and credible.

Because a 50 GT LTL vapes one in a single shot?

One of the funniest things he does is that the uses TDiC but claims that there are fireballs the size of 25% of the planets surface around there somewhere.

When I get some freetime, I'm gonna have to get back into the game there.

[Rightous Fist Of Heaven]

Yeah you do that. He is good in babbling a lot of numbers but when it comes to as simple things as actually analyzing a goddamn picture correctly he cant do it.

And get back to the game as soon as you can.

[Master of Ossus]

What a dumbass. Tell him about the yield of the Borg torpedoes used to attack Montana in ST:FC. The ones that didn't even knock down buildings from orbit.

I would also recommend reminding him that the weapons on the Acclamator are measured in joules PER SHOT PER BARREL, and not for all four of them. He further has no clue how much larger the weapons on the ISD are than the Acclamator weapons.

[Anarchist Bunny]

HA! I got a responce. Should I go post the calcs or should I just not waste my time?

[Anarchist Bunny]

And I didn't even use LTLs, I just used 50 MTLs and the 6 big ones.

[Ender]

HA! I got a responce. Should I go post the calcs or should I just not waste my time?

please

[Rightous Fist Of Heaven]

Reinforcements are allways a good thing. A crushing victory is the best one