A friend posed this question to me today:
My friend wrote:How many proton torpedos would be needed to take down a star destroyer? Assuming it isnt fighting back or anything, and just taking it.
I responded with the following:
I wrote:Technically speaking, you could lob an infinite number of torpedoes at a star destroyer and it would just smile at you.
Shields work by dissipating the energy thrown at them. Star destroyer shields are particularly powerful. In the extended literature (and the movies), the only way to take down shields is to overwhelm their dissipative capabilities with a huge surge of firepower ("Concentrate all fire on that super star destroyer!") which you need to target at a shield generator. The idea is to punch through the shields and damage a local projector so that you can then attack the hull.
There's a particularly good example of this in one of the X-wing books. There's also a weapon called a Torpedo Sphere used for planetary sieges. What it does is basically sit in orbit and lob ungodly amounts of torpedoes at the same exact spot on the shields until they overwhelm the shield and punch through, destroying the planetary projector.
I didn't want to leave him with my vague assertions, so I poked around the board for a bit to find the particular X-wing quote in question. I then told him this (bold emphasis mine, added to point out relevant parts):
Then I wrote:Quote from "Bacta War" (bold emphasis mine):
Engaging in a straight-up fight with even a Victory-class Star Destroyer like the Corrupter would be suicide for a squadron of X-wings. [..] If the whole squadron fired a salvo of torpedoes at the same time, they could certainly bring the Star Destroyer's shields down, but any captain worth his rank cylinders would roll the ship to present undamaged shields and keep shooting.
Followed with:
I then wrote:A squadron in SW is 12 ships. X-wings each carry 6 torpedoes, fired in 'salvos' of 2. So if the entire squadron (12) fired a salvo of torpedoes (12*2 = 24) at the same time, they'd take down one facing of a
Victory (smaller, weaker than
Imperator-class seen in the OT movies) destroyer's shields, at which point the ship can simply be rolled over so the other side of its shields can block incoming fire.
From "Essential Guide to Weapons and Technology":
When overloaded by incoming energy charges, a shield projector's matrix boards will burn out rather than flooding the generator with energy and destroying the entire shield system. Tech crews can repair burned out-out projectors in just a few minutes to get the shields back up to full power.
So repairing that much shield collapse takes a matter of minutes. Attacking a capital ship with starfighters alone is a bad plan
![Wink ;)](./images/smilies/icon_wink.gif)
So, having said all that, I have a few questions of my own.
![Arrow :arrow:](./images/smilies/icon_arrow.gif)
Did I explain it to him correctly, more or less? I know I glossed over a few things, but he's not a tech-centric guy. As a layman's definition, how is it?
![Arrow :arrow:](./images/smilies/icon_arrow.gif)
Given that we now know the reactor power of
Venators, and that
Victorys are roughly analogous warships, is it possible to codify the precise amount necessary to overload a shield facing on a
Victory, given the above quote? If so, what is it?