A question for anyone knowledgeable in physics
Moderator: Alyrium Denryle
A question for anyone knowledgeable in physics
Hello, a good fellow at a forum I frequent led me to the good people of this forum. He said they were up to this. I need a formula, please, if possible, help me out. Basically, I need to know how high a ball is after being applied a variable amount of force, in a variable amount of gravity. If you need to know how long the force is applied, then that is variable too. The mass of the object, too, is variable. And, if possible, please tell me how to imput all the data (What format, joules etc). Thank you for your time.
Last edited by Wooh on 2002-12-13 10:19pm, edited 3 times in total.
- SWPIGWANG
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k.e=p.e=m*g*h=F*d
g is gravitation field strengh, find it by using GM/R^2 , M being the source of gravity (usually the planet)
m is the mass of the object
F is the force net
d is the net distance the force is applied
convert it from time using d = (1/2)*(F/m)*t^2
h is the height, or your result.
This formula should work for short distances (no big change in g) and low speeds where other factors can be ignored (friction and relativitic crap..etc)
g is gravitation field strengh, find it by using GM/R^2 , M being the source of gravity (usually the planet)
m is the mass of the object
F is the force net
d is the net distance the force is applied
convert it from time using d = (1/2)*(F/m)*t^2
h is the height, or your result.
This formula should work for short distances (no big change in g) and low speeds where other factors can be ignored (friction and relativitic crap..etc)
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If everything is continuously variable, then you're looking at calculus, and probably a numerical solution rather than an analytical solution.
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"you guys are fascinated with the use of those "rules of logic" to the extent that you don't really want to discussus anything."- GC
"I do not believe Russian Roulette is a stupid act" - Embracer of Darkness
"Viagra commercials appear to save lives" - tharkûn on US health care.
http://www.stardestroyer.net/Mike/RantMode/Blurbs.html
Change that probably to a definetly.
Wooh, I have the sinking suspiscion that you are after Tsiolkovsky's Rocket Equation, variable mass, variable gravity and variable force? Yep sounds like the usual suspect.
Or are you looking for a generic equation to determine the heigt of the ball, and then use some kind of spreadsheet or program like MATLAB to see the different heights when the variables are varried? Sorry I am just seeking a little crarity that's all.
Wooh, I have the sinking suspiscion that you are after Tsiolkovsky's Rocket Equation, variable mass, variable gravity and variable force? Yep sounds like the usual suspect.
Or are you looking for a generic equation to determine the heigt of the ball, and then use some kind of spreadsheet or program like MATLAB to see the different heights when the variables are varried? Sorry I am just seeking a little crarity that's all.
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The second one, except I want to use it in a program, where if have the time and the 4 variables (mass, gravity, force, and time that force is applied), i can get the height at say, 1 second, 2 second, etc. Nothing quite as complex as the rocket formula, because none of the variables change.Crown wrote:Change that probably to a definetly.
Wooh, I have the sinking suspiscion that you are after Tsiolkovsky's Rocket Equation, variable mass, variable gravity and variable force? Yep sounds like the usual suspect.
Or are you looking for a generic equation to determine the heigt of the ball, and then use some kind of spreadsheet or program like MATLAB to see the different heights when the variables are varried? Sorry I am just seeking a little crarity that's all.
In that case;
v^2 = u^2 + 2as
a = accleration and is negative.
u = initial velocity
v = final velocit
At greatest height, final velocity is equal to 0.
The initial velocity is a little tricky, but can be found as follows;
F = ma
F = m*(u/t)
therefor u = t*(F/m)
You could assume that the Force is applied instanteousley, t = 1, and then you can get u very easily.
Which gives you a greatest height of;
s = (-u^2)/2a
To see the different heights you could use Excel, by setting up a data table (see Excel's help page) but this will limit you to only being able to vary two of the variables.
v^2 = u^2 + 2as
a = accleration and is negative.
u = initial velocity
v = final velocit
At greatest height, final velocity is equal to 0.
The initial velocity is a little tricky, but can be found as follows;
F = ma
F = m*(u/t)
therefor u = t*(F/m)
You could assume that the Force is applied instanteousley, t = 1, and then you can get u very easily.
Which gives you a greatest height of;
s = (-u^2)/2a
To see the different heights you could use Excel, by setting up a data table (see Excel's help page) but this will limit you to only being able to vary two of the variables.
Η ζωή, η ζωή εδω τελειώνει!
"Science is one cold-hearted bitch with a 14" strap-on" - Masuka 'Dexter'
"Angela is not the woman you think she is Gabriel, she's done terrible things"
"So have I, and I'm going to do them all to you." - Sylar to Arthur 'Heroes'
I think that's right, and I hope that that's what you were after.
Η ζωή, η ζωή εδω τελειώνει!
"Science is one cold-hearted bitch with a 14" strap-on" - Masuka 'Dexter'
"Angela is not the woman you think she is Gabriel, she's done terrible things"
"So have I, and I'm going to do them all to you." - Sylar to Arthur 'Heroes'
- Durandal
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Re: A question for anyone knowledgeable in physics
Wow ... this sounds like a complex problem. If mass, force and gravity are variable, you'll probably be looking at a triple integral. Your output unit will obviously be meters, since you're looking for height.Wooh wrote:Hello, a good fellow at a forum I frequent led me to the good people of this forum. He said they were up to this. I need a formula, please, if possible, help me out. Basically, I need to know how high a ball is after being applied a variable amount of force, in a variable amount of gravity. If you need to know how long the force is applied, then that is variable too. The mass of the object, too, is variable. And, if possible, please tell me how to imput all the data (What format, joules etc). Thank you for your time.
Could you give us the exact problem? This is difficult to do analytically. Is the ball being launched straight up? What is the initial velocity? What is the launching angle?
Since gravitational acceleration is variable, you'll probably be looking at the equation
F = GMm/r^2
as your base equation.
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- Wicked Pilot
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Re: A question for anyone knowledgeable in physics
I want to keep them variable, it is going to get user imput and then figure out the height.Durandal wrote:Wow ... this sounds like a complex problem. If mass, force and gravity are variable, you'll probably be looking at a triple integral. Your output unit will obviously be meters, since you're looking for height.Wooh wrote:Hello, a good fellow at a forum I frequent led me to the good people of this forum. He said they were up to this. I need a formula, please, if possible, help me out. Basically, I need to know how high a ball is after being applied a variable amount of force, in a variable amount of gravity. If you need to know how long the force is applied, then that is variable too. The mass of the object, too, is variable. And, if possible, please tell me how to imput all the data (What format, joules etc). Thank you for your time.
Could you give us the exact problem? This is difficult to do analytically. Is the ball being launched straight up? What is the initial velocity? What is the launching angle?
Since gravitational acceleration is variable, you'll probably be looking at the equation
F = GMm/r^2
as your base equation.
An example: You have a ball, resting on a platform. The ball weighs 2 grams. The gravity of the area the ball is in is 3x the normal earth gravity. For 5 seconds, 10 newtons of net force is added - this is the force over the amount needed to break free of the gravitational pull so the ball doesn't just sit on the platform. Find when the ball peaks, at how high, when the ball hits the ground, and say...the height of the ball at 2 seconds, 5 seconds, 7 second, 9 seconds, any amount of seconds, really.
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Alright, first we find the initial velocity of the ball at release. For this we will use the equation:Wooh wrote:An example: You have a ball, resting on a platform. The ball weighs 2 grams. The gravity of the area the ball is in is 3x the normal earth gravity. For 5 seconds, 10 newtons of net force is added - this is the force over the amount needed to break free of the gravitational pull so the ball doesn't just sit on the platform. Find when the ball peaks, at how high, when the ball hits the ground, and say...the height of the ball at 2 seconds, 5 seconds, 7 second, 9 seconds, any amount of seconds, really.
vi=at, a=F/m, vi=Fi/m
(i=impulse time)
(vi=initial velocity)
(F=force)
(m=mass)
now we will need to know how long it will take for the ball to reach a final, zero velocity. We get this by the equation:
vf=vi-gt, t=(vi-vf)/g
(vf=final velocity)
(g=acceleration due to gravity)
(t=time)
now we fing the height using the equation:
h=.5gt^2
(h=height ball will achieve)
therefore, if we add together all the equations, we get the mother equation of:
h=.5g(((fi/m)=vf)/g)^2
I hope this helps. Somebody please be so kind as to check my work, I'm not perfect.
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vf is an unnessecary term because vf=0.Wicked Pilot wrote:h=.5g(((fi/m)-vf)/g)^2
sorry, as I said, sombody should check my work
Also, using i is confusing. It is better to use t.
You can simplify this equation further by canceling the g.
Therefore, h=(.5(Ft/m)^2)/g
Where h is the maximum height of the ball, F is the force applied at launch (above the force of gravity), t is the time for which said force is applied, and g is the acceleration due to gravity.
data_link has resigned from the board after proving himself to be a relentless strawman-using asshole in this thread and being too much of a pussy to deal with the inevitable flames. Buh-bye.
is h only the maximum height (peak), or the height at the given value for t?data_link wrote:vf is an unnessecary term because vf=0.Wicked Pilot wrote:h=.5g(((fi/m)-vf)/g)^2
sorry, as I said, sombody should check my work
Also, using i is confusing. It is better to use t.
You can simplify this equation further by canceling the g.
Therefore, h=(.5(Ft/m)^2)/g
Where h is the maximum height of the ball, F is the force applied at launch (above the force of gravity), t is the time for which said force is applied, and g is the acceleration due to gravity.
h is the maximun height. t is the time for which the force is applied.
If you want to find the height at one particular moment in time, then you would use h = vi - .5gt^2, where h is height, vi is the initial velocity of the ball, g is the acceleration due to gravity, and t is the time after launch.
If you want to find the height at one particular moment in time, then you would use h = vi - .5gt^2, where h is height, vi is the initial velocity of the ball, g is the acceleration due to gravity, and t is the time after launch.
data_link has resigned from the board after proving himself to be a relentless strawman-using asshole in this thread and being too much of a pussy to deal with the inevitable flames. Buh-bye.