nasor wrote:I’ve never taken any classes in relativity, but this explanation does not make sense to me. It implies that time dilation should be linear with velocity, when (according to the time dilation equations) it isn’t.
If, as in your example, I’m moving at .9 C parallel to a light beam then time would have to pass at 1/10 normal speed for me in order for the light beam to continue to travel away from me at C. But in fact if you plug .9C into T=To / (1-V^2/C^2)^.5, time would only pass at a bit less than half for normal speed.
Because in the stationary frame of reference, you're traveling forward at .9 c, chasing after a pulse of light going at c, and all the while, I see that your rulers are too short in the direction of travel. When you travel at speed, in my frame of reference (in which you're moving) all your clocks are ticking slowly than mine by a factor of 1/γ (where γ=√(1 - v²/c²) ), and all of your rulers are shorter than mine by a factor of γ, as well as moving forward at v = .9 c.
Suppose that we've synchronized our watches such that a light pulse passes you at (0,0). A second later (t = 1s), you locate the light pulse at x = c(1s). From your frame of reference, the speed of this light pulse is w = c(1s)/1s = c. What is the speed of this pulse from my frame of reference?
The Lorentz transformation for translating between your coordinates (t, x) and mine (t', x') is:
t' = γ(t - vx/c²)
x' = γ(x - vt)
The light pulse passes you at our coordinates (0,0) as well. Our coordinates for the coordinates (c(1s), 1s) in your frame (where the light pulse is after 1s of your time) is (γ(.1s), cγ(.1s)), so w = x'/t' = cγ(.1s)/γ(.1s) = c.
And there you have it. The speed of light is the same from all frames of references. We agree on practically nothing else: we don't agree on the position of the light pulse, we don't agree on the time the light pulse reaches that position, and we don't even agree on the zero axes. (We do agree on the origin, but that's arbitrary anyway.) The Lorentz transformation involves not only a change in time, but also of space, and the moving frame's position. This is why it is not linear.
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