However, I thought I should mention that while playing with a calculator, I realized that if one applies a exponent of 4 to any warp factor(ie: 1, 9.9, etc), you get a factor of C which seems similar to some factors others have suggest for warp.
It is unclear. The linear scale for hyperdrives, as demonstrated in the RPG, is obviously not accurate. From EU sources, it appears to be some sort of a logarithmic scale, or something even stranger.
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umm wasnt Warp factor once the Warp speed cubed IE warp 2 was 8c
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Addendum: The proper formula would be an asymptotal one, where as x gets closer and closer to 10, y grows infinitely larger. Also, depending on the relationship between warp and transwarp, you could have a warp function on one side of the asymptote, and a transwarp function on the other side, so long as each function is undefined at x = 10. Kennedy's formula does not satisfy this requirement, therefore it is wrong.
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Hyperdrive: unknown, not enough data to generate an actual formula.
Transwarp, regular warp, slipstream, etc: whatever the writers want it to be for this week's episode.
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Durandal wrote:Addendum: The proper formula would be an asymptotal one, where as x gets closer and closer to 10, y grows infinitely larger. Also, depending on the relationship between warp and transwarp, you could have a warp function on one side of the asymptote, and a transwarp function on the other side, so long as each function is undefined at x = 10. Kennedy's formula does not satisfy this requirement, therefore it is wrong.
What about an analogy with relativistic/newtonian mechanics ? The formula is accurate for low warp speeds, but as warp gets higher than, say, factor 8, the formula changes and y tend to infinite as x gets close to 10 ?
I sort of liked Darth Wong's suggestion for the Voyager FTL formula: sacrificing live chickens to the Warp Gods while speaking incantations in the tongue of the Old Ones.
Durandal wrote:Addendum: The proper formula would be an asymptotal one, where as x gets closer and closer to 10, y grows infinitely larger. Also, depending on the relationship between warp and transwarp, you could have a warp function on one side of the asymptote, and a transwarp function on the other side, so long as each function is undefined at x = 10. Kennedy's formula does not satisfy this requirement, therefore it is wrong.
What about an analogy with relativistic/newtonian mechanics ? The formula is accurate for low warp speeds, but as warp gets higher than, say, factor 8, the formula changes and y tend to infinite as x gets close to 10 ?
I dunno, maybe. I guess. How hard is it to create a formula with a denominator of x-10, though?
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The Specialist wrote:W = (SQRT(10)/SQRT(10-ABS(V))-1)*[Maximum velocity possible using warp]
This doesn't work, as the denominator at x = 10 is negative. Unless you meant this:
v(x) = [C/(sqrt(10 - x))] - 1
where
C = (sqrt(10))(V_max)
on the domain
D: {x| 0 < x < 10}
That function would approach infinity rather quickly because of the square root on the bottom, though. Perhaps too rapidly, but it's still better than Kennedy's.
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IIRC, there is a fixed number stated for Transwarp. In one episode of Voyager, the Delta Flyer was clocked at 400LY/sec as stated by Lameway. It was in part 2 of the episode where a borg queen wanted seven to rejoin the collective.
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Just remembered, that formula doesn't work because it includes the term for maximum achievable speed using warp. That term would be the local maximum of the function. The local max is a point where the derivative is zero. In the case of a function describing warp factors, the function must keep increasing exponentially as it goes to x = 10. The slope of the tangent line, therefore, would get closer and closer to infinity, which is why a local max can never exist at an asymptote.
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