ISD Reactor
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NomAnor15
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ISD Reactor
So in another thread I was informed that the reactor of an ISD was approximately 1.4E6 cubic meters, and that the ISD as a whole was about 1.4E8 m^3. So the reactor is about 1/100th of the ISD's volume. Does anybody know how this compares to a modern day aircraft carrier, for example?
"I wish I wish I hadn't killed that fish." - Homer Simpson
Huh. That's less than 10 condoms per person. Though, assuming an even split between gender, that's almost 20 condoms per penis, so I certainly hope that would suffice for the three weeks they're there. -Alferd Packer
This sentence is false.
This sentence is false.
I was discussing reactors with a friend at work (he was a reactor tech on Lincoln) and he said that this was on the order of the size of a typical carrier reactor. There are two per carrier these days. Volume of this design is about 1600m³. A carrier has a volume of, estimating off of a diagram, about half a million cubic meters. So a carrier's reactors (just the bare reactor vessels, mind) are about 0.6% of the carrier by volume.
A reasonable upper limit is arrived at by approximating the ISD by a box 1600 m long, 1000 m wide, and 200 m tall, which gives something like 3.2e8 m^3. I figured that that was overacheiving by a factor of 2 or 3, but I don't have the equipment to do accurate scaling, but I wouldn't be surprised if the upper limit overcounts by a factor of 5 or 6. (Edit: the percentage volume of the reactor is still going to be somewhere between 1% and 10% of the ISD, even if 9.2e7 m^3 is an upper limit.)FTeik wrote:Doesn't the ISD have a volume of 9.0E7 cubicmeters at best?
Actually, I'll see if I can arrive at a lower limit. To do it, one need only figure the volume of the hull accurately, and note that the superstructure wasn't counted. It should be a relatively simple double integral.
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I arrived at a lower limit of 6.3e7 m^3 by taking Dr Saxton's measurements of an ISD here, assuming four-way symmetry of the hull, that the forward angle of an ISD's dagger is 40 degrees and that the rear angle of the dagger is 120 degrees, integrating along the length of an ISD, and then multiplying by four since I'd only found a fourth of the total volume of the hull. This does not include superstructure. If anyone's interested, I can post details of the calculation.
So, at best, the reactor is 2.2% of the ISD's volume.
So, at best, the reactor is 2.2% of the ISD's volume.
A Government founded upon justice, and recognizing the equal rights of all men; claiming higher authority for existence, or sanction for its laws, that nature, reason, and the regularly ascertained will of the people; steadily refusing to put its sword and purse in the service of any religious creed or family is a standing offense to most of the Governments of the world, and to some narrow and bigoted people among ourselves.
F. Douglass