Dankayo BDZ Incident- firepower for cratering surface

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darth_timon
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Dankayo BDZ Incident- firepower for cratering surface

Post by darth_timon »

Hello one and all.

I have been discussing with a friend recently the firepower requirements for a Base Delta Zero event. I have referenced both Mike's site and that of Curtis Saxton but he isn't buying it. He has referenced st-v-sw.net a few times, though generally he doesn't, but his overall stance is that there is no requirement (with Dankayo at least) for the Star Destroyers to quickly bombard the planet.

He has put forward kiloton to megaton-level firepower for a Star Destroyer. I have attempted to put forward, in terms of maths, how much firepower would be needed to evenly crater the surface of a world, then work out how much time is needed to. I have been conservative and used the surface area of Pluto as a reference, rather than a larger world.

My maths are as follows:
To evenly crater even a world as small as Pluto (17 million km2) with craters of 0.178km in diametre you would need 95505617 18KT bombs. That works out at 1,719,101,106KT- or in other words, 1,719TT. That is simply to crater Pluto, and that is with kiloton-level weaponry.

Using your own estimation of 30 shots per second, and assuming no more than 18KT firepower for all the turbolasers on the ships, and three ships (thus 90 shots per second), that works out at 1,620KT per second. In one hour there are 3,600 seconds- so, 1,620KT x 3,600 = 5,832,000KT, or 5.8GT per hour.

Perhaps a better way to describe it is 0.58TT per hour from three ISDs working in tandem.

At that rate of fire, to crater a Pluto-sized world, it would take three ISDs 2,963 hours. That's 17 weeks.

Obviously this was not the case, and there is a case for Dankayo being bigger than Pluto.

Now lets repeat the exercise. Only this time, lets assume 18MT rather than 18KT. This gives us craters that are 1.7km in diametre.

To crater the surface of Pluto with 18MT weaponry you would need 28,900,000 bombs/shots.

18MT x 28,900,000 = 520,200,000MT. 'Only' 520TT.

Once again, 90 seconds per second x 18MT = 1,620MT per second, or 1.62GT. 1.62GT x 3,600 seconds (1 hour) = 5,832GT- or 5.832TT.

In one day, three ISDs could deliver 139.968TT. It would take them just under four days to completely crater the surface of Pluto.

For a single ISD under the first, 18KT scenario, it would take 51 weeks to evenly crater the surface of Pluto. So you can imagine, with that kind of firepower, how long it would take to crater a world like earth. I think we can both agree that ISDs pack greater firepower than the kiloton range.

For a single ISD under scenario 2, it would take one ISD twelve days to crater the surface of Pluto. This is plainly unreasonable. An ISD is a warship, built for battle, and not intended to be wasted on spending days on cratering a planet, yet we know that the surface of Dankayo was indeed, evenly cratered.

Under scenario 1, a single ISD would take an hour to deliver 1.9GT.

Under scenario 2, a single ISD would take an hour to deliver 1.9TT.
I would like to point out that maths and science are not my strong suits. I got a C at GCSE science and an E at GCSE maths. So I expect my calculations to be wrong. Simply put, I am posting this because I wish to understand where I went wrong and how to avoid such mistakes in the future.
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Ender
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Post by Ender »

you are treating a laser shot like a bomb blast. This is incorrect. Mike has a page typed up detailing the differences and appropriate maths, but as a rule of thumb a laser needs to have 6 orders of magnitude more energy then the bomb to create an equivalent shockwave.

Rather then proving all that math a better solution would be to do a thermodynamic analysis (search the archives, Kane Starkiller did a good one here) or prove the required reactor power to move the ship based off its volume and observed performance.

Your big mistake is in letting him dictate too much to you. Just do an energy analysis and point to the observed ROF at the Battle of Coruscant (1 shot per 1.5 sec was observed at its fastest) to show the lowest possible yield of the weapons.
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Connor MacLeod
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Post by Connor MacLeod »

I thought the "like a bomb" thing took timeframe greatly into account as well as energy (thta was power as well, not as energy.) IIRC the difference in energy was alot different (20-50x differencec IIRC.)
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darth_timon
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Post by darth_timon »

Thanks for the assistance guys. I'm currently looking around Mike's site, trying to establish how much different a TL bolt would be from a bomb blast. I've checked the turbolaser page and I'm wondering if the clue I'm looking for is concerning rocky material being vapourised (ala asteroids in TESB). Am I warm or horribly cold?
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