I have a problem with this derivation already. Things break because the forces on an object vary with space, not time. A uniform force in space will just cause an acceleration, even if the force is nonconstant in time. A nonuniform force will cause stresses and failure, because in order for the object to keep a rigid shape, internal forces must even the forces out, as it were. In order for a bar to keep the same shape being pulled from one end, the bar must exert forces on its other end such that the average acceleration along the bar is the same — otherwise, one part of the bar goes at a different speed from other parts, and the bar flies apart.Steel wrote:Heres the outline of how it might work.
Let us suppose that there is some quantity "stress" that the ship can only withstand a certain amount of, and this is what limits the closest approach to a star.
Now let us use the changing potential/force theory, and try and define this mysterious "stress" quantity as the rate of change of the (magnitude of the) gravitational force on the ship.
So Stress = dF/dt
Now, this is not to say that stress could not be an indirect function of time. It can. But when you start out with the basics wrong, no guarantee can be made that it will work.
As such, there is already a first-order approximation for tital forces:
F = 2GMm/R² ∆r/R
That is, the force on a ship at a particular point is 2∆r/R times the weight of the object in that gravity field. Since most objects are small compared to typical R's, this is usually insignificant, and the above equation good enough.
However, this is not true for a ship in hyperspace, and I am about to do something you should never, ever do at home: I am going to combine classical physics with relativistic physics, in a regime where relativistic physics produces silly answers without nonkosher modifications.
Since we are going very very fast, somewhere around 10 millon c, let's take a look at what would happen to the relative length of the ship. We're going to make the replacement γ → γi for v > c, so length "contraction" becomes
∆x' = ∆x/γi
At typical hyperspatial speeds of millions of c, this translates to a length expansion of a factor of ten million, and if we take a typical ship is on the order of a few kilometers, the above calculation yields lengths greater (though not that much greater) than a planetary radius, and forces on the order of the ship's own weight.
Of course, the tidal forces calculation I stated above is only good when ∆r/R is small, and ∆r/R here is not small. Adding in the other terms, it's clear that the maximum force on the really stretched out ship is on the order of its own weight in that gravity. This isn't a concern around planets, but around objects with significant gravity (such as stars), this could get significant.