Okay, here's my assessment of the superlaser's speed, as depicted when firing on Alderaan. First, have a look at
this. It's an assessment of the varius lengths and angles involved.
The only article I could find via a quick search on Google suggested that motion control cameras like those used in Star Wars generally had lens focal lengths of 3.5-5mm, so I have provided for both scenarios. The angle measurements come from LightWave 3D 7.5, which calculates horizontal and vertical field of views given a lens focal length and output resolution (in this case, 720x330, the size of the actual visible frame from my Star Wars ANH VHS captures). I chose to go with the motion control lens because it's what was used for most (if not all) of the space shots in Star Wars, to the best of my knowledge. If someone can tell me different, I'll be happy to recalculate.
A few definitions below:
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Alderaan diameter: 119px
Overall view width: 720px
a = side opposite angle A; 1/2 overall view width
b = side opposite angle B; 'distance' to Alderaan
c = hypotenuse of triangle abc; irrelevant in this calculation
A = angle opposite side a; btw. ~73° and ~78°
B = angle opposite side b; irrelevant
C = 90° angle opposite side c; irrelevant
Now, I realize that Alderaan was certain
not in the middle of the frame, as my image depicts that it is. However, I
think its position can be ignored given the distance involved, since the camera would likely have to be set to focus at 'inifinite' distance to get Alderaan to focus the way it is.
So, since we know one side length and one angle of our 'frame-size' triangle, we can determine the distance to Alderaan via the following calculation:
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a = 360px
b = X px
A = 73.010° -or- 77.925°
tan(A) = a/b
tan(A) = 360px/Xpx --> Xpx = 360px/tan(A)
Xpx = 360px/tan(73.010) | 360px/tan(77.925)
Xpx = 360px/3.2729 | 360px/4.6745
Xpx = 109.99px | 77.014px
So, Alderaan's distance from the frame is therefore either 77.014px or 109.99px. However, assessing the "Z-depth" of Alderaan in pixels doesn't help us measure the speed of the superlaser. In order to determine the km:px ratio, we need to know how big Alderaan is. We can do one of two things here: assume Alderaan is identical in size to Earth -or- use published RPG material (*gasp!* a sinner!) to garner Alderaan's size. Either way:
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Earth diameter: 12,756km
12,756km/119px = 107km/px
-or-
RPG diameter: 12,500km
12,500km/119px = 105km/px
So, using this scaled against the
b side of the triangle pixel...
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105km/px * 77.014px = 8,090km (conservative)
107km/px * 109.99px = 11,800km (generous)
Now, this is all assuming I haven't made some incorrect assumption about the mathematics involved (that would be most embarassing

! ) and about the lens being used. However, this is not the end of the discussion. One thing remains: how fast did the superlaser get there?
Well, for the sake of simplicity, I'm going to assume that the superlaser travelled directly from the camera's viewpoint to Alderaan. Elsewise, the 3D trigonometry involved will probably make my head explode (assessing the diameter of the superlaser beam, figuring out its distance from the camera, etc, etc, etc). Suffice it to say, whatever figure I attain below will be a
low-end estimate, even using the generous distance, due to the fact that the superlaser will have traveled a greater distance than I'm assuming.
In any case, the superlaser entered the frame on 03:15 of my firing video clip. It reaches Alderaan (impact with the planetary shield) at frame 03:22. As such, it is travelling for 7-8 frames, depending on which frames you decide to count as 'travelling' frames. Using this information:
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8,090km / 8frames * 30 frames/sec = 30,300 km/s
11,800 km / 7 frames * 30 frames/sec = 50,600 km/s
This is clearly and blatantly far below lightspeed. Unless my methodology is way off, then the 75,000 km figure stated in the ANH novelization is simply grossly inaccurate.
However, I don't know if my method here works. As such...
Possible sources of error:
Incorrect lens focal length
Incorrect assessment of trigonometry principles involved
Offset in position of superlaser beam from lens center
If I am incorrect in the first two, please let me know. I know the latter introduces some error, but I'm not really up to calculating it at 2:30am
